The relation between voltage sensitivity ` 'sigma_(V)'` and current sensitiviy `sigma_(i)` of moving coil galvanometer if its resistance is `'G'` is

Options

A. `(sigma_(i))/(G) = sigma_(v)`
B. `(sigma_(v))/(G) = sigma_(i)`
C. `(G)/(sigma_(v)) = sigma_(i)`
D. `(G)/(sigma_(i)) = sigma_(v)`

Answer

A

Explanation

`sigma_(v) = (sigma_(i))/(R ) implies sigma_(v) = (sigma_(i))/(G)`