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A square conducting loop of side length ...

A square conducting loop of side length L carries a current I.The magnetic field at the centre of the loop is (dependence on L)

A

Independent of L

B

Proportional to `L^(2)`

C

Inversely proportional to L

D

Linearly proportional to L

Text Solution

Verified by Experts

The correct Answer is:
C

For one side
`B_(1) = (mu_(0) I)/(4pi r) [sin 45^(@) + sin 45^(@)]`
`= (mu_(0) xx 2l)/(4pi (L)) [ (1)/(sqrt2) + (1)/(sqrt2)]`
`= (2 sqrt2 mu_(0) I)/(4pi L)`

B due to square
`B = 4B_(1) = (mu_(0))/(pi ) (2sqrt2 I)/(L) , { r = sqrt(((L)/(sqrt2))^(2) - ((L)/(2))^(2))= sqrt((L^2)/(2) - (L^2)/(4)) = (L)/(2)}`
`therefore B prop (1)/(L)`
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