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A long straight wire carries a certain current and produces a magnetic field `2 xx 10^-4 Weber//m^2` at a perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire. An electron situated at 5cm from the wire moves with a velocity `10^7 m//s` towards the wire along perpendicular to it. The force experience by the electron will be (charge on electron `1.6 xx 10^-19 C)`.

A

3.2 N

B

`3.2 xx 10^(-16)` N

C

`1.6 xx 10^(-16)` N

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
B

`F = qvB = 1.6 xx 10^(-19) xx 10^(7) xx 2 xx 10^(-4) = 3.2 xx 10^(-16) N`
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