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A magnet of length 0.1 m and pole streng...

A magnet of length `0.1 m` and pole strength `10^(-4)` A.m. is kept in a magnetic field of `30 Wb//m^(2)` at an angle `30^(@)`. The couple acting on it is `…xx10^(-4)Nm`.

A

7.5

B

`3.0`

C

`1.5`

D

`6.0`

Text Solution

Verified by Experts

The correct Answer is:
C
`tau= MB sin theta= q_(m) lB sin 30^(@)`
`= 10^(-4) xx 0.1 xx 30 xx (1)/(2) = 1.5`
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