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The time period of oscillation of a free...

The time period of oscillation of a freely suspended bar magnet with usual notations is given by

A

`T= 2pi sqrt((I)/(MB_(H)))`

B

`T= 2pi sqrt((MB_(H))/(I))`

C

`T= sqrt((I)/(MB_(H)))`

D

`T= 2pi sqrt((B_(H))/(MI))`

Text Solution

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The correct Answer is:
A
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