Two identical bar magnets are placed on above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is T. The time period of esch magnet in the same field is

Options

A. `sqrt2T`
B. `2^((1)/(4))T`
C. `2^(-(1)/(4))T`
D. `2^(-(1)/(2))T`

Answer

C

Explanation

`T= 2pi sqrt((2I)/(sqrt2MH))`
`because T.= 2pi sqrt((I)/(MH))`
`therefore T.= (T)/(2^(1//4))= 2^(-(1)/(4))T`