A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. The time period of vibration is found to be 2 sec. The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be 2 seconds. Then the angle of dip is

Options

A. `0^(@)`
B. `30^(@)`
C. `45^(@)`
D. `90^(@)`

Answer

C

Explanation

`T_(1)= 2pi sqrt((I)/(MB_(V))), T_(2)= 2pi sqrt((I)/(MB_(H)))`
As `T_(1)= T_(2) rArr B_(V)= B_(H)`
`delta = 45^(@)`