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A bar magnet is oscillating in the earth...

A bar magnet is oscillating in the earth's magnetic field with a period T. What happens to its period and motion if its mass is quadrupled

A

Motion remains S.H.M. with time period = 2T

B

Motion remains S.H.M. with time period = 4T

C

Motion remains S.H.M. and period remains nearly constant

D

Motion remains S.H.M. with time period `= (T)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`T prop sqrt("mass")`
`rArr (T)/(T_(1))= sqrt((m)/(m_(1))) = sqrt((m)/(4m)) = (1)/(2) rArr T_(2)= 2T`
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