If a coil of `40` turns and area `4.0 cm^(2)` is suddenly remove from a magnetic field, it is observed that a charge of `2.0xx10^(-4)C` flows into the coil. If the resistance of the coil is `80Omega`, the magnetic flux density in `Wb//m^(2)` is

Options

A. 0.5
B. `1.0`
C. 1.5
D. `2.0`

Answer

B

Explanation

`q=(NDeltavarphi)/R`
`rArrNDeltavarphi=2xx10^(-4)xx80rArrNBA=2xx10^(-4)xx80`
`rArrB=(2xx10^(-4)xx80)/(40xx4xx10^(-4))=1Wb//m^(2)`.