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As shown in figure, a metal rod complete...

As shown in figure, a metal rod completes the circuit. The circuit area is perpendicular to a magnetic field with `B = 0.15 T`. If the resistance of the total circuit is `3 Omega`, how large a force is needed to move the rod as indicated with a constant speed of 2 m/s?

A

`3.75xx10^(-3)N`

B

`3.75xx10^(-2)N`

C

`3.75xx10^(2)N`

D

`3.75xx10^(-4)N`

Text Solution

Verified by Experts

The correct Answer is:
A
`F=IlB=(Blv)/R*lB`
= `(B^(2)l^(2)v)/R=((0.15)^(2)xx(0.5)^(2)xx2)/3`
= `3.75xx10^(-3)N`.
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