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A coil of resistance 400Omega is placed ...

A coil of resistance `400Omega` is placed in a magnetic field. If the magnetic flux `phi` (wb) linked with the coil varies with time `t` (sec) as `f=50t^(2)+4`, the current in the coil at `t=2` sec is

A

0.5 A

B

0.1 A

C

`2` A

D

`1` A

Text Solution

Verified by Experts

The correct Answer is:
A
`varphi=50t^(2)+4rArr|e|=(dvarphi)/dt=100t`
`t = 2, |e| = 200`
Current (I) = `e/R=200/400=0.5A`.
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