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A circular disc of radius 0.2 m is place...

A circular disc of radius `0.2 m` is placed in a uniform magnetic fied of induction `(1)/(pi) ((Wb)/(m^(2)))`
in such a way that its axis makes an angle of `60^(@)` with The magnetic flux linked with the disc is

A

0.08 Wb

B

0.01 Wb

C

0.02 Wb

D

0.06 Wb

Text Solution

Verified by Experts

The correct Answer is:
C
`R=0.2m,B=1/piWb//m^(2),theta=60^(@)`
`varphi=BAcostheta`
= `B(pir^(2))cos60^(@)=0.02Wb`.
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