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The current passing through a choke coil...

The current passing through a choke coil of `5` henry is decreasing at the rate of `2 ampere//sec`. The e.m.f. developing across the coil is

A

10 V

B

`-10` V

C

2.5 V

D

`-2.5` V

Text Solution

Verified by Experts

The correct Answer is:
A
`|e|=L(di)/(dt)=5xx2=10V`
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