A transformer having efficiency of `90%` is working on `200 V` and `3 kW` power supply. If the current in the secondary coil is `6A`, the voltage across the secondary coil and current in the primary coil respectively are

Options

A. 450 V, 13.5 A
B. 600 V, 15 A
C. 300 V, 15 A
D. 450 V, 15 A

Answer

D

Explanation

`P_(S)=3kW=90/100=2.7kW`
`I_(S)=6A`
`V_(S)=(2.7xx10^(3))/6=450V`
`I_(P)=(3xx10^(3))/200=15A`.