When an electron in hydrogen atom is excited, from its `4`th to `5`the stationary orbit, the change in angular momentum of electron is (Planck's constant: `h = 6.6 xx 10^(-34) J-s`)

Options

A. `4.16 xx 10^(-34) J-s`
B. `3.32 xx 10^(-34) J-s`
C. `1.05 xx 10^(-34)J-s`
D. `2.08 xx 10^(-34) J-s`

Answer

C

Explanation

Change in the angular momentum
`Delta L= L_(2)- L_(1) = (n_(2)h)/(2pi) - (n_(1)h)/(2pi)`
`Delta Delta L= (h)/(2pi) [n_(2)-n_(1)] = (6.6 xx 10^(-34))/(2 xx 3.14) xx (5-4)`
`=1.05 xx 10^(-34J` -sec