Electrons in a certain energy level `n=n_(1)` can emit 3 spectral lines. When they are in another energy level, `n=n_(2)`, they can emit 6 spectral lines. The orbital speed of the electrons in the two orbits are in the ratio

Options

A. `4:3`
B. `3:4`
C. `2:1`
D. `1:2`

Answer

A

Explanation

Since, number of spectral line `= (n(n-1))/(2)`
`3= (n_(1) (n_(1)-1))/(2) rArr n_(1)= 3`
`6= (n_(2) (n_(2)-1))/(2) rArr n_(2)= 4`
Since, `v_(n) prop (1)/(n) rArr (v_(1))/(v_(2)) = (n_(2))/(n_(1))= (4)/(3)`