In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportinal to `(n =` principle quantum number)

Options

A. `n^(-1)`
B. n
C. `n^(-2)`
D. `n^(2)`

Answer

D

Explanation

`n^(th)` orbit Bohr radius `(r_(n))= (epsi_(0)n^(2) h^(2))/(pi Z m e^(2))`
i.e., `r prop n^(2)`