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The de-Broglie wavelength of an electron...

The de-Broglie wavelength of an electron in the first Bohr orbit is

A

Equal to one fourth the circumference of the first orbit

B

Equal to half the circumference of the first orbit

C

Equal to twice the circumference of the first orbit

D

Equal to the circumference of the first orbit

Text Solution

Verified by Experts

The correct Answer is:
D
Since `2pi r_(n) = n lamda`
i.e., `2pi r_(1)= lamda`
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