In the nth orbit, the energy of an electron `E_(n)= -( 13.6)/(n^(2)) eV` for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be

Options

A. 10.2 eV
B. 12.1 eV
C. 13.6 eV
D. 3.4 eV

Answer

A

Explanation

Since, `E_(n)= (-13.6)/(n^(2)) eV`
`E_(2)= (-13.6)/((2)^(2))= -3.4eV`
Now, `E_(2)- E_(1)= -3.4 - (-13.6) = 10.2eV`