Ionization potential of hydrogen atom is `13.6 V`. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy `12.1 eV`. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

Options

A. one
B. Two
C. Three
D. Four

Answer

C

Explanation

Final energy `= -13.6 + 12.1 = 1.51eV`
i.e., `(-13.6)/((3)^(2))= - 1.51`eV
`therefore n=3`
No. of spectral lines emitted `= (n (n-1))/(2)`
`= (3(3-1))/(2)= 3`