The ionisation energy of hydrogen atom is `13.6 eV`. Following Bohr's theory, the energy corresponding to a transition between the `3`rd and the `4`th orbit is

Options

A. 3.40 eV
B. 1.51 eV
C. 0.85 eV
D. 0.66eV

Answer

D

Explanation

`E_(n)= (-13.6)/(n^(2))`
`E_(3)= (-13.6)/(9) = - 1.51eV and E_(4)= (-13.6)/(16)= - 0.85eV`
`therefore E_(4)- E_(3)= 0.66eV`