Calculate the highest frequency of the emitted photon in the Paschen series of spectral lines of the hydrogen atom.

Options

A. `3.7 xx 10^(14)Hz`
B. `9.1 xx 10^(15)Hz`
C. `10.23 xx 10^(14)Hz`
D. `29.7 xx 10^(15)Hz`

Answer

A

Explanation

`(1)/(lamda) = R ((1)/(n_(1)^(2))- (1)/(n_(2)^(2)))`
`rArr (f)/(c)= R ((1)/(n_(1)^(2))- (1)/(n_(2)^(2))) rArr f= Rc ((1)/(n_(1)^(2))- (1)/(n_(2)^(2)))`
For Paschen series and highest frequency
`n_(1)= 3, n_(2) oo`
`therefore f_("max") = (1.097 xx 10^(7) xx 3 xx 10^(8))/(9)`
`rArr f_("max") = 3.7 xx 10^(14)Hz`