Two energy levels of an electron in an atom are separated by 2.3 eV. The frequency of radiation emitted when the electrons go from higher to lower level is

Options

A. `6.95 xx 10^(14)Hz`
B. `3.68 xx 10^(15) Hz`
C. `5.6 xx 10^(14)Hz`
D. `9.11 xx 10^(15)Hz`

Answer

C

Explanation

`Delta E= h f`
`rArr f= (2.3 xx 1.6 xx 10^(-19))/(6.6 xx 10^(-34)) = 5.6 xx 10^(14) Hz`