A double charged lithium atom is equivalent to hydrogen whose atomic number is `3`. The wavelength of required radiation for emitted electron from first to third Bohr orbit in `Li^(++` will be (Ionization energy of hydrogen atom is `13.6 eV`)

Options

A. `182.51 Å`
B. `177.17 Å`
C. `142.25 Å`
D. `113.74 Å`

Answer

D

Explanation

`Delta E= E_(3)- E_(1)`
`rArr (hc)/(lamda) = 13.6 Z^(2) [(1)/(1^(2))- (1)/(3^(2))]`
`rArr lamda= (6.6 xx 10^(-34) xx 3 xx 10^(8))/(108.8 xx 1.6 xx 10^(-19)) = 113.74 Å`