In hydrogen atom the electron is moving round the nucleus with velocity `2.18xx10^(6)`m/s in an orbit of radius `0.528Å`. The cenripetal acceleration of the electron is

Options

A. `9 xx 10^(18) m//s^(2)`
B. `9 xx 10^(22) m//s^(2)`
C. `9 xx 10^(-22)m//s^(2)`
D. `9xx 10^(12) m//s^(2)`

Answer

B

Explanation

Centripetal acceleration `a_(c)= (v^(2))/(r)= ((2.18 xx 10^(6))^(2))/(0.528 xx 10^(-10)) rArr a_(c) = 9 xx 10^(22) m//s^(2)`