In a Rutherford scattering experiment when a projectile of change `Z_(1)` and mass `M_(1)` approaches s target nucleus of change `Z_(2)` and mass `M_(2)`, te distance of closed approach is `r_(0)`. The energy of the projectile is

Options

A. Directly proportional to `M_(1) xx M_(2)`
B. Directly proportional to `z_(1)z_(2)`
C. Inversely proportional to `z_(1)`
D. Directly proportional to mass `M_(1)`

Answer

B

Explanation

If `r_(0)` is the distance of closest approach, Kinetic energy = Potential energy
`rArr K= (1)/(4pi epsi_(0)).((z_(1)e)(z_(2)e))/(r_(0)) rArr r_(0)= (1)/(4pi epsi_(0)).(z_(1)z_(2) e^(2))/(K)`