If an electron in a hydrogen atom jumps from the `3rd` orbit to the `2nd` orbit, it emits a photon of wavelength `lambda`. When it jumps form the `4th` orbit to the `3dr` orbit, the corresponding wavelength of the photon will be

Options

A. `(20)/(7) lamda`
B. `(20)/(13) lamda`
C. `(16)/(25) lamda`
D. `(9)/(16) lamda`

Answer

A

Explanation

Transition : `3 rarr 2 rArr` Wavelength `lamda`
Transition : `4 rarr 3 rArr` Wavelength `lamda.=` ?
`((1)/(lamda)= R_(H)Z^(2) ((1)/(2^(2))- (1)/(3^(2))))/((1)/(lamda.) = R_(H)Z^(2) ((1)/(3^(2))- (1)/(4^(2))))`
`rArr (lamda.)/(lamda)= (20)/(7) rArr lamda.= (20 lamda)/(7)`