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In a material medium, when a position me...

In a material medium, when a position meets an electron both the particles annihilate leading to the mission of two gamma ray photon. This process forms the basis of an important diagnostic procedure called

A

MRI

B

PET

C

CAT

D

SPECT

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The correct Answer is:
B
In a material medium, when a positron meets an electron both the particles annihilate leading to the emission of two `gamma` ray photons. This process forms the basis of an important diagnostic procedure called PET.
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The positron is a fundamental particle with the same mass as that of the electron and with a charge equal to that of an electron but of opposite sign. When a positron and an electron collide, they may annihilate each other. The energy corresponding to their mass appears in two photons of equal energy. Find the wavelength of the radiation emitted. [Take : mass of electron = (0.5//c^(2))MeV and hc = 1.2 xx 10^(-12) MeV-m , where h is the Planck's constant and c is the velocity of light in air.

Two very small particles are executing SHM along very near parallel lines about the same mean position, same amplitude and the same frequency. At t = 0 both the particle are moving with speed of 1m//sec but on the opposite side of the mean position and having same direction of velocity at a distance of 5cm from the mean position. At t = 4sec they are at the same position moving with speed of 1m//sec but in opposite direction. Assuming that this is the minimum time form t = 0 where they are meeting for the 1st time. If the maximum speed of either particle is (xpi)/(4sqrt(2))cm//sec Find x

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Photoelectrons are emitted when 400 nm radiation is incident on a surface of work - function 1.9 eV. These photoelectrons pass through a region containing a-particles. A maximum energy electron combines with an a -particle to from a He^+ ion, emitting a single photon in this process. He^+ ions thus formed are in their fourth excited state. Find the energies in eV of the photons lying in the 2 to 4 eV range, that are likely to be emitted during and after the combination. [Take, h = 4.14xx10^(-15) eV -s]

photoelectrons are emited when 40 nm radiation is incident on a surface of work function 1.9 eV These photoelectron pass tjhrough a ragain cotaining a - particle A maximum energy electron conbines with an a - particle to from a He^(+) ion emitting a single photon in this process He^(+) ions thus formed are in their fourth excited state find the energies in eV of the photons typing is the 2 to 4 eV rage, that are likrly to be emitted during and after the combiution [Take h = 4014 xx 10^(-15) eV s]

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