If radius of the `._(13)^(27)Al` nucleus is taken to be `R_(AI)`, then the radius of `._(53)^(125)Te` nucleus is nearly

Options

A. `(5)/(3) R_(Al)`
B. `(3)/(5) R_(Al)`
C. `((13)/(53))^(1//3) R_(Al)`
D. `((53)/(13))^(1//3) R_(Al)`

Answer

A

Explanation

`R= R_(0) A^((1)/(3))`
`(R_(Al))/(R_(Te)) = ((27)/(125))^((1)/(3)) = (3)/(5) rArr R_(T_(e)) = (5)/(3) R_(Al)`