A radioactive nucleus of mass `M` emits a photon of frequency `v` and the nucleus recoils. The recoil energy will be

Options

A. hv
B. `Mc^(2)- hv`
C. `(h^(2)v^(2))/(2Mc^(2))`
D. Zero

Answer

C

Explanation

Energy `(E) = (p^(2))/(2M) = (((hv)/(c))^(2))/(2M) = (h^(2)v^(2))/(2M c^(2))`