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A radioactive nucleus X undergoes sponta...

A radioactive nucleus `X` undergoes spontaneous decay in the sequence
z X to z-1 B to z-3 C to z-2 D, where Z is the atomic number of element Z. The possible decay particles in the sequence are:

A

`alpha, beta^(+), beta^(-)`

B

`beta^(+), alpha, beta^(-)`

C

`beta^(-), alpha, beta^(+)`

D

`alpha, beta^(-), beta^(+)`

Text Solution

Verified by Experts

The correct Answer is:
B
`""_(Z)^(A) X overset(beta^(+))rarr ""_(Z-1)B overset(alpha)rarr ""_(Z-3)C overset(beta^(-))rarr ""_(Z-2)D`
`beta^(+)` decreases atomic number by 1
`alpha` decreases atomic number by 2
`beta^(-)` increases atomic number by 1.
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