A silicon specimen is made into a `P`-type semiconductor by dopping, on an average, one helium atoms per `5xx10^(7)` silicon atoms. If the number density of atoms in the silicon specimen is `5xx10^(28) at om//m^(3)` then the number of acceptor atoms in silicon per cubic centimeter will be

Options

A. `2.5xx10^(30)"atoms/cm"^(3)`
B. `1.0xx10^(13)"atoms/cm"^(3)`
C. `1.0xx10^(15)"atoms/cm"^(3)`
D. `2.5xx10^(36)"atoms/cm"^(3)`

Answer

C

Explanation

`N_(A)=(5xx10^(28))/(5xx10^(7))=10^(21)//m^(3)`
Number of acceptor atoms -
`N_(A)=(10^(21))/((10^(2))^(3)cm^(3))=10^(15)//cm^(3)`