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In a reverse biased diode, when the appl...

In a reverse biased diode, when the applied voltage changes by `1V`, the current is found to change by `0.5muA`. The reversebiase resistance of the diode is

A

`2xx10^(5)Omega`

B

`2xx10^(6)Omega`

C

`200 Omega`

D

`2 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
Reverse resistance = `(DeltaV)/(DeltaI)=(1)/(0.5xx10^(-6))=2xx10^(6)Omega`
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