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For the transistor circuit shown below, ...

For the transistor circuit shown below, if `beta=100`, voltage drop between emitter and base is `0.7V` then value of `V_(CE)` will be

A

`10` V

B

`5` V

C

`13` V

D

`0` V

Text Solution

Verified by Experts

The correct Answer is:
C
`i_(B)=(5-0.7)/(8.6)=0.5mA`
:. `i_(C)=betaI_(B)=100xx0.5=50` mA
:. `V_(CE)=V_(C C)-I_(C)R_(L)=18-50xx10^(-3)xx100=13V`
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