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In a PNP transistor working as common-ba...

In a `PNP` transistor working as common-base amplifier, current gain is `0.96` and current is `7.2 mA`. The base current is

A

`0.4` mA

B

`0.2` mA

C

`0.29` mA

D

`0.35` mA

Text Solution

Verified by Experts

The correct Answer is:
C
`alpha=(I_(C))/(I_(E))implies0.96=(I_(C))/(7.2mA)impliesI_(C)=6.912` mA
:. `I_(B)=I_(E)-I_(C)=0.288~~0.29 mA`
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