A change of 0.04 V takes place between the base and the emitter when an input signal is connected to the CE transistor amplifier. As a result, `20 mu A` change takes place in the base current and a change of 2 mA takes place in the collector current. Find the input resistance and A.C. current gain

Options

A. `2kOmega, 100`
B. `1kOmega, 100`
C. `2kOmega, 200`
D. `1kOmega, 200`

Answer

A

Explanation

`DeltaV_(i)=0.04V`
`DeltaI_(B)=20mu A`
`DeltaI_(C)=2mA`
`r_(i)=(DeltaV_(i))/(DeltaI_(B))=(0.04)/(20xx10^(-6))=(4xx10^(4))/(20)=2kOmega`
`beta=(DeltaI_(C))/(DeltaI_(B))=(2xx10^(-3))/(20xx10^(-6))=100`