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The resonce frequency of the tank cuircu...

The resonce frequency of the tank cuircuit of an oscillator when `L=(1)/(pi^(2))mH` and `C=0.04 muF` are connected in parellel is

A

`250` kHz

B

`25` kHz

C

`2.5` kHz

D

`25` MHz

Text Solution

Verified by Experts

The correct Answer is:
B
`f=(1)/(2pisqrt(LC))=(1)/(2pi)sqrt((1)/((10)/(pi^(2))xx10^(-3)xx0.04xx10^(-6)))`
= `25` kHz .
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