A zener diode has a contact potential of 1 V in the absence of biasing. It undergoes Zener breakdown for an electric field of `10^(6)` V/m at the depletion region of p-n junction. If the width of the depletion region is 2.5 `mu`m, what should be the reverse biased potential for the Zener breakdown to occur ?

Options

A. `3.5` V
B. `2.5` V
C. `1.5` V
D. `0.5` V

Answer

B

Explanation

`E=10^(6)V//m,d=2.5xx10^(-6)m`
`V_("breakdown")=Exxd=10^(6)xx2.5xx10^(-6)=2.5` V .