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Consider the junction diode as ideal. Th...

Consider the junction diode as ideal. The value of current flowing through AB is:

A

`0A`

B

`10^(-2)A`

C

`10^(-1)A`

D

`10^(-3)A`

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(PN)=4-(-6)=10V`
`:.` Diode is in FB
`I=(10)/(1xx10^(3))=10^(-2)A`
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