Consider an `n-p-n` transistor amplifer in common-emitter configuration. The current gain of the transistor is `100`. If the collector current changes by `1mA`, what will be the change in emitter current?

Options

A. `1.1mA`
B. `1.01mA`
C. `0.01mA`
D. `10mA`

Answer

B

Explanation

`beta=(DeltaI_(C))/((DeltaI_(B))impliesDeltaI_(B)=(10^(-3))/(100)=10^(-5)A`
`:.DeltaI_(E)=DeltaI_(B)+DeltaI_(C)=0.01+1=1.01mA`