In a CE transistor amplifier, the audio signal voltage across the collector resistance of `2kOmega` is `2V`. If the base resistance is `1kOmega` and the current amplification of the transistor is 100, the input signal voltage is:

Options

A. `0.1V`
B. `1.0V`
C. `1mv`
D. `10mv`

Answer

D

Explanation

`I_(C)=(2)/(2xx10^(3))=1mA`
`beta=(I_(C))/(I_(B))impliesI_(B)=(10^(-3))/(100)=10^(-5)A`
`V_(i)=R_(B)I_(B)=10^(3)xx10^(-5)=10^(-2)`Volt
`V_(i)=10mv`