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In a common emitter (CE) amplifier havin...

In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductor 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will

A

`(5)/(4)G`

B

`(2)/(3)G`

C

`1.5G`

D

`(1)/(3)G`

Text Solution

Verified by Experts

The correct Answer is:
B

Voltage gain `=(DeltaV_(C))/(DeltaV_(B))=(R_(L)DeltaI_(C))/(DeltaV_(B))=g_(m)R_(L)` [`g_(m)=` transconductor `=(DeltaI_(C))/(DeltaV_(B))]`
`:.(A_(V_(1)))/(A_(V_(2)))=(g_(m_(1)))/(g_(m_(2)))implies(G)/(A_(V_(2)))=(0.03)/(0.02)impliesA_(V_(2))=(2)/(3)G`.
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