In the following common emitter configur...

In the following common emitter configuration an n-p-n transistor with current gain `beta` = 100 is used. The output voltage of the amplifier will be

`10mV`

`0.1V`

`1.0V`

`10V`

Text Solution

Verified by Experts

The correct Answer is:

`V_(0)=A_(V)xxV_(i)=beta((R_(L))/(R_(i)))V_(i)=100((10)/(1))xx1xx10^(-3)=1V`

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