Two point masses A and B having masses in the ratio `4:3` are separated by a distance of 1m. When another point mass C of mass M is placed in between A and B, the force between A and C is `(1/3)^(rd)` of the force between B and C. Then the distance C from A is

Options

A. `2/3m`
B. `1/3m`
C. `1/4m`
D. `1/5m`

Answer

A

Explanation

`m_A=4m,m_B=3m,d=1m`
`m_c=M,F_(AC)=1/3`

`rArr(Gxx4mxxm)/(x^2)=(G3mxxm)/(3(1-x)^2)`
`rArr(1-x)/x=1/2`
`rArr1=(3x)/2rArrx=2/3m`