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Two stars of mass m1 and m2 are parts of...

Two stars of mass `m_1` and `m_2` are parts of a binary system. The radii of their orbits are `r_1` and `r_2` respectively, measured from the C.M. of the system. The magnitude of gravitational force `m_1` exerts on `m_2` is

A

`(m_1m_2G)/((r_1+r_2)^2)`

B

`(m_1G)/((r_1+r_2)^2)`

C

`(m_2G)/((r_1+r_2)^2)`

D

`(m_1+m_2)/((r_1+r_2)^2)`

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The correct Answer is:
To find the magnitude of the gravitational force \( F \) that mass \( m_1 \) exerts on mass \( m_2 \) in a binary star system, we can use Newton's law of universal gravitation. The formula for the gravitational force between two masses is given by: \[ F = \frac{G \cdot m_1 \cdot m_2}{d^2} \] where: - \( F \) is the gravitational force, - \( G \) is the gravitational constant (\( 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \)), - \( m_1 \) and \( m_2 \) are the masses of the two stars, - \( d \) is the distance between the two masses. ### Step-by-Step Solution: 1. **Identify the Distance Between the Masses**: The distance \( d \) between the two stars can be expressed in terms of their respective orbital radii \( r_1 \) and \( r_2 \). Since \( r_1 \) and \( r_2 \) are measured from the center of mass (C.M.) of the system, the total distance \( d \) between the two stars is: \[ d = r_1 + r_2 \] 2. **Substitute the Distance into the Gravitational Force Formula**: Now, we can substitute \( d \) into the gravitational force formula: \[ F = \frac{G \cdot m_1 \cdot m_2}{(r_1 + r_2)^2} \] 3. **Final Expression**: Thus, the magnitude of the gravitational force that mass \( m_1 \) exerts on mass \( m_2 \) is: \[ F = \frac{G \cdot m_1 \cdot m_2}{(r_1 + r_2)^2} \]

To find the magnitude of the gravitational force \( F \) that mass \( m_1 \) exerts on mass \( m_2 \) in a binary star system, we can use Newton's law of universal gravitation. The formula for the gravitational force between two masses is given by: \[ F = \frac{G \cdot m_1 \cdot m_2}{d^2} \] where: - \( F \) is the gravitational force, ...
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ERRORLESS-GRAVITATION-Assertion and Reason
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  3. Statement -1: Gravitational force between two particles is negligibly ...

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  6. Assertion : If a pendulum falls freely, then its time period becomes i...

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  7. Statement I: If the earth suddenly stops rotating about its axis, then...

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  8. Assertion : The difference in the value of acceleration due to gravity...

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  9. Assertion: For the plantes orbiting around the sun, angular speed, lin...

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  10. Assertion : A force act upon the earth revolving in a circular orbit...

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  11. Assertion: The speed of revolution of an artificial satellite revoving...

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  12. Assertion : Gravitational potential of earth at every place on it is...

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  13. Assertion : Even when orbit of a satellite is elliptical, its plane of...

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  14. Assertion : A planet moves faster, when it is closer to the sun in i...

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  15. Assertion : Orbital velocity of a satellite is greater than its esca...

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  16. Assertion : The speed of satellite always remains constant in an orb...

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  17. Assertion : Earth has an atmosphere but the moon does not. Reason ...

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  18. Assertion: The time period of geostationary satellite is 24 hrs. Rea...

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  19. Assertion : The principle of superposition is not valid for gravitat...

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  20. Assertion: Two different planets have same escape velocity. Reason:...

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