An earth satellite of mass `m` revolves in a circular orbit at a height `h` from the surface of the earth. R is the radius of the earth and `g` is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

Options

A. `(gR^2)/(R+h)`
B. `gR`
C. `(gR)/(R+h)`
D. `sqrt((gR^2)/(R+h))`

Answer

D

Explanation

`v_0=sqrt((GM)/r)=sqrt((GM)/((R+h)))=sqrt((GM)/(R^2).(R^2)/(R+h))=sqrt((gR^2)/((R+h)))`