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In a satellite if the time of revolution...

In a satellite if the time of revolution is `T`, then kinetic energy is proportional to

A

`1/T`

B

`(1)/(T^2)`

C

`(1)/(T^3)`

D

`T^(-2//3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`v=sqrt((GM)/r)rArrv^2prop1/r`
Since, `r^3propT^2`
`rpropT^(2//3),v^2propT^(-2//3),thereforeKEpropT^(-2/3)`.
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