A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth, where R is the radius of the earth. The time period of another satellite at a height of 2.5 R from the surface of the earth is …… hours.

Options

A. 10 hr
B. `(6//sqrt2)hr`
C. 6 hr
D. `6sqrt2` hr

Answer

D

Explanation

`T^2propr^3rArr(T_1^2)/(T_2^2)=((7R)/(3.5R))^3`
`rArr(24)/(T_2)=(2)^(3/2)=2sqrt2`
`T_2=24/(2sqrt2)=6sqrt2hr`