A satellite of mass `m` is orbiting the earth (of radius `R`) at a height `h` from its surface. The total energy of the satellite in terms of `g_(0)`, the value of acceleration due to gravity at the earth's surface,

Options

A. `-(2mv_0R^2)/(R+h)`
B. `(mv_0R^2)/(2(R+h))`
C. `-(mg_0R^2)/(2(R+h))`
D. `(Rmg_0R^2)/(R+h)`

Answer

C

Explanation

Total energy`=-(GM_em)/(2(R+h))`
`becauseg_0=(GM_e))/(R^2)rArrM_e=(g_0R^2)/G`
`therefore` Energy `=-(mg_0R^2)/(2(R+h))`