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The gravitational force between two obje...

The gravitational force between two objects is proportional to `1//R` (and not as `1//R^(2)`) where `R` is separation between them, then a particle in circular orbit under such a force would have its orbital speed `v` proportional to

A

`1//R^2`

B

`R^0`

C

`R^1`

D

`1//R`

Text Solution

Verified by Experts

The correct Answer is:
B
`(GMm)/R=(mv^2)/RrArrv_0=sqrt(GM)`
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